2013年7月2日星期二

Pass4Test IBM 000-183 Prüfung Übungen und Antworten

Vielleicht können Sie auch die relevanten Schulungsunterlagen in anderen Büchern oder auf anderen Websites finden. Aber wenn Sie die Produkte von Pass4Test mit ihnen vergleichen, würden Sie herausfinden, dass unsere Produkte mehr Wissensgebiete umfassen. Sie können auch im Internet teilweise die Fragen und Antworten zur IBM 000-183 Zertifizierungsprüfung kostenlos herunterladen, so dass Sie die Qualität unserer Produkte testen können. Die Gründe, dass Pass4Test exklusiv umfassende Materialien von guter Qualität bieten können, liegt darin, dass wir ein exzellentes Expertenteam hat. Sie bearbeiten die neuesten Fragen und Antworten zur IBM 000-183 Zertifizierungsprüfung nach ihren IT-Kenntnissen und Erfahrungen. Deshalb sind die Fragen und Antworten zur IBM 000-183 Zertifizierungsprüfung von Pass4test bei den Kandidaten ganz beliebt.


Um in der IT-Branche große Fortschritte zu machen, entscheiden sich viele ambitionierte IT-Profis dafür, an der IBM 000-183 Zertifizierungsprüfung zu beteiligen und somit das IT-Zertifikat zu bekommen. Wegen des schwierigkeitsgrades der IBM 000-183 Zertifizierungsprüfung ist die Erfolgsquote sehr niedrig. Aber es ist doch eine weise Wahl, an der IBM 000-183 Zertifizierungsprüfung zu beteiligen, denn in der konkurrenzfähigen IT-Branche heute muss man sich immer noch verbessern. Und Sie können auch viele Methoden wählen, die Ihnen beim Bestehen der Prüfung helfen.


Exam Code: 000-183

Prüfungsname: IBM (IBM WebSphere Mesage Broker V7.0, Solution Development)

Pass4Test Ihnen helfen, echte IBM 000-183 Prüfungsvorbereitung in einer echten Umgebung zu finden. Wenn Sie ein Anfänger sind und Ihre beruflichen Fähigkeiten verbessern wollen, werden die Fragen zur IBM 000-183 Zertifizierungsprüfung von Pass4Test Ihnen helfen, Ihren Traum Schritt für Schritt zu erfüllen. Wir werden alle Ihren Fragen bezüglich der Prüfung lösen. Innerhalb eines Jahres bieten wir Ihnen kostenlosen Update-Service. Bitte schenken Sie unserer Website mehr Aufmerksamkeit.


Pass4Test hat riesiege Expertenteam, die Ihnen gültige Schulungsressourcen bieten. Sie haben die Prüfungen in den letzten Jahren nach ihren Erfahrungen und Kenntnissen untersucht. Und endlich kommen die zielgerichteten Fragen und Antworten auf, die den IT-Kandidaten große Hilfe bieten. Nun können Sie im Internet teilweise die Prüfungsfragen und Anworten zur IBM 000-183 Zertifizierungsprüfung kostenlos als Probe herunterladen. Viele IT-Fachleute haben bewiesen, dass Pass4Test sehr zuverlässig ist. Wenn Sie die zielgerichteten Prüfungsfragen von Pass4Test benutzt haben, können Sie normalerweise die IBM 000-183 Zertifizierungsprüfung bestehen. Schicken Sie doch die Produkte von Pass4Test in den Warenkorb. Sie werden sehr wahrscheinlich der nächste erfolgreiche IT-Fachmann.


000-183 prüfungsfragen Demo kostenlos downloden: http://www.pass4test.de/000-183.html


NO.1 The solution developer has been informed by the SAP team that the userid and password for the SAP
test environment needs to be replace
D.What is the EASIEST way to reconfigure userid and password for an SAP EIS adapter?
A.Modify the deployment descriptor in the affected bar files and redeploy them to all required locations.
B.Use the following command against the affected broker(s): mqsisetdbparms <brokername> -n
eis::<adaptername> -u <username> -p <password>
C.Use the following command against the affected broker(s): mqsichangeproperties <brokername> -c
eis::<adaptername> -o SAP -u <username> -p <password>
D.Rerun the Adapter Connection Wizard for the component, enter the updated values and redeploy the
component to all required locations.
Answer: B

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NO.2 A customer needs to dynamically choose which web service URL to call from a WSDL in the
WebSphere Service Registry and Repository (WSRR), based on a company acronym in the input
message received by Message Broker.Which node should the solution developer choose when
implementing this type of retrieval operation?
A.EndpointLookup
B.RegistryLookup
C.EndpointRetrieval
D.DatabaseRetrieval
Answer: A

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NO.3 A developer needs to create an asynchronous messaging application to connect to a third party which
uses a programming interface known as Message Queue Interface (MQI).Which transport protocol should
the developer use?
A.MQ
B.FTP
C.JMS
D.XMS
Answer: A

IBM prüfungsfrage   000-183   000-183   000-183

NO.4 A large company needs to interface their legacy application with a newly acquired Enterprise
Information System (EIS) application called Siebel CRM.Which transport service will the developer use to
discover metadata and send requests to the EIS system?
A.MQ Link for R3
B.WebSphere Broker Adapters
C.WebSphere Broker File Transport
D.WebSphere Business Integration Adapter
Answer: B

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NO.5 A developer is tasked with designing a message flow, utilizing an XSLTransform node.Which location is
searched first by the broker, to determine the name of the style sheet to use?
A.The LocalEnvironment.
B.The BAR file overrides.
C.The XSLTransform node properties.
D.Inside the message XML data.
Answer: D

IBM echte fragen   000-183   000-183   000-183

NO.6 Which one of the following advantages does the Enterprise Service Bus deliver over traditional
point-to-point solutions?
A.Scalability
B.Adaptability
C.Redundancy
D.Performance
Answer: B

IBM echte fragen   000-183 zertifizierungsantworten   000-183   000-183   000-183

NO.7 A developer has a message flow that consists of an MQInput node, Compute node and MQOutput
node.The message is parsed by the XMLNSC domain.The Compute node will extract the name and age
of each player, then send them onto the register players application to have the team registered.The input
message that the Compute node will be processing is shown below.
What MUST be done to access the information from the first player?
A.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputBody.Body.Player[1]
B.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputBody.DetailedMsg.Body.Player[1]
C.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[0]C.Set
OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[0]
D.Set OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[1]D.Set
OutputRoot.XMLNSC.RegPlayer.Player[NextCount] = InputRoot.DetailedMsg.Body.Player[1]
Answer: B

IBM   000-183 echte fragen   000-183   000-183 zertifizierungsantworten   000-183

NO.8 When a message is received by an Input node in a message flow, the message assembly is
created.Which tree or trees are populated when an error free message is received by a FileInput node?
A.The Message tree only.
B.The Message tree and Environment tree.
C.The Message tree and LocalEnvironment tree.
D.The Message tree, Environment tree, LocalEnvironment tree, and ExceptionList tree.
Answer: C

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NO.9 As part of an Order Process flow, a developer must add a new section to an existing XML message.The
relevant section of the incoming message is as follows:
The developer must add the following Order Item, to fall in the correct numeric sequence: <OrderItem>
<Number>333</Number> </OrderItem> How would the developer achieve this?
A.DECLARE FieldRef REFERENCE TO OutputRoot; CREATE FIELD
OutputRoot.XMLNSC.OrderMsg.OrderItem[3].Number AS FieldRef; SET FieldRef = '333';
B.DECLARE FieldRef REFERENCE TO OutputRoot.XMLNSC.OrderMsg.OrderItem[2]; CREATE
NEXTCHILD OF FieldRef NAME 'Number'; SET FieldRef = '333';
C.DECLARE FieldRef REFERENCE TO OutputRoot.XMLNSC.OrderMsg.OrderItem[2]; CREATE
NEXTSIBLING OF FieldRef NAME 'OrderItem'; SET FieldRef.Number = '333';
D.DECLARE FieldRef REFERENCE TO OutputRoot.XMLNSC.OrderMsg.OrderItem[2]; CREATE
NEXTSIBLING OF FieldRef AS FieldRef NAME 'OrderItem'; SET FieldRef.Number = '333';
Answer: D

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NO.10 A message flow reads a file, record by record.Based on the content of each record, it will be propagated
to one or more output queues.The File Input node has the Transaction property set to yes and all output
nodes are configured to be Automatic node has the transaction property set to yes and all output nodes
are configured to be automatic In the event that flow execution is interrupted by a hardware failure, which
one of the following is true?
A.Processing will resume at the beginning of the file; previously created messages will be duplicated.
B.Processing will resume at the beginning of the file; previously created messages will be backed out.
C.Processing of the file resumes at the last checkpoint; any extraneous messages will have been rolled
back.
D.The file will be deleted or archived depending on the setting of the File Input node; unprocessed
records will be missing from the output.
Answer: A

IBM zertifizierung   000-183   000-183

NO.11 View the Exhibit:
The above flow processes a large incoming file line by line once every four hours.Performance is
unsatisfactory even though the server has spare memory and unused processors.Configuring additional
instances does not improve this.The following pair of flows was suggested by an architect.The first flow
will slice the incoming file into messages without any further processing, which is to be done by the
second flow.
What is the expected outcome if the second flow is configured with a large number of additional
instances?
A.Throughput will improve somewhat.Message sequence will not be affected.
B.Throughput will be unaffecte
D.Message sequence will most likely be affected.
C.Throughput will improve significantly.Message sequence will most likely be affected.
D.Throughput will deteriorate slightly due to the extra queuing.Message sequence will not be affected.
Answer: C

IBM   000-183   000-183   000-183   000-183

NO.12 A solution developer needs to help a software company to decide whether to use HTTP nodes or
SOAP nodes in developing web services.Which of the following benefits would the solution developer use
in support of SOAP nodes over HTTP nodes?
A.Support for a broker wide listener.
B.Support for runtime validation against WSDL.
C.Support for other web service standards, like REST and XML-RPC.
D.Support for external Web servlet container to provide listener support for a larger number of concurrent
sessions.E.Automatic processing of Message Transmission Optimization Mechanism (MTOM).
Answer: B,E

IBM   000-183   000-183   000-183 zertifizierung

NO.13 Consider the following ESQL code snippet from a Compute node.
What is the value of OutputRoot.XMLNSC?
A.NULL
B.<Winner/>
C.<Winner Name="Robert"/>
D.<Winner><Name>Rocky</Name></Winner>
Answer: D

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NO.14 The following flow processes data from an input queue and builds a file.A Timeout Notification node
has been configured to send a message to the Finish File ¯ s t e r m i na l o f t he ile Output node once every
hour.As a result, a file named hourly Record Collection.dat will be written to theFinish File terminal of the
File Output node once every hour.As a result, a file named hourly Record Collection.dat?will be written to
the designated destination directory.
It is expected the previous file will be removed before the next file is written in its place.If this has not
happened, what are the options available to the solution developer on the File Output node?
A.Overwrite (replace) the old file or append to the old file.
B.Overwrite (replace) the old file or rename the old file in place by adding a timestamp or throw an
exception.
C.Overwrite (replace) the old file or archive the old file with or without a time stamp appended to the file
name or throw an exception.
D.Overwrite (replace) the old file or append to the old file or archive the old file (with or without a time
stamp appended to the file name.)
Answer: C

IBM   000-183 prüfung   000-183   000-183 prüfungsfragen

NO.15 A developer needs to generate a monotonically increasing sequence number for each message in a
given message flow.What is the MOST efficient way to achieve this?
A.Use the Create Sequence operator of ESQL.
B.Use the Generate Sequence operator of Java.
C.Use the Sequence function of an external database.
D.Use the Sequence node of WebSphere Message Broker.
Answer: D

IBM   000-183 zertifizierungsantworten   000-183

NO.16 Which Message Broker artifact type is not analyzed by Impact Analysis?
A..esql
B..mset
C..msgmap
D..msgflow
Answer: B

IBM zertifizierung   000-183   000-183   000-183   000-183

NO.17 In a message flow, a developer needs to enrich an employee's record with information from a
database.Consider this input message.
Which of the ESQL statements in the response options will produce the following output message?
A.SET OutputRoot.XMLNSC.Employee.Name[] = (SELECT ITEM E.EmpName from Database.Employee
as E where E.EmpNumber = InputBody.Employee.Number);
B.SET OutputRoot.XMLNSC.Employee.Name[] = (SELECT E.EmpName AS Name from
Database.Employee as E where E.EmpNumber = InputBody.Employee.Number);
C.SET OutputRoot.XMLNSC.Employee = THE(SELECT E.EmpName from Database.Employee as E
where E.EmpNumber = InputBody.Employee.Number);
D.SET OutputRoot.XMLNSC.Employee = THE(SELECT ITEM E.EmpName AS Name from
Database.Employee as E where E.EmpNumber = InputBody.Employee.Number);
Answer: A

IBM zertifizierung   000-183 prüfung   000-183   000-183   000-183

NO.18 A company has decided to use WebSphere Message Broker to integrate several legacy systems which
generate batch files into the company WebSphere MQ backbone.What is the quickest way the developers
can accomplish this task?
A.Build a user defined node.
B.Create a user defined extension.
C.Create a program that processes the batch files into WebSphere MQ messages and then send the
messages to WebSphere Message Broker for processing.
D.Use the Record Distribution to WebSphere MQ one-way built-in pattern.
Answer: D

IBM zertifizierungsantworten   000-183 prüfungsunterlagen   000-183   000-183   000-183   000-183 dumps

NO.19 Consider the following two implementations of a request/response pattern.1) Asynchronous with a
separate flow for the response logic using an MQInput node
2)
Synchronous, completing the round trip in the same flow pulling the response message with an MQGet
node
Which of the following is FALSE?
A.Multiple flow instances will not help throughput in either implementation.
B.The synchronous implementation will require more memory, especially in scenarios with large
messages and high throughput requirements.
C.Given sufficient resources, the synchronous implementation will perform better in cases where large
amounts of data (i

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